TUGAS
MATA KULIAH JARINGAN INFORMASI DIGITAL
DIBIMBING OLEH : MOH. SAFII, S.KOM
OLEH ACH. NIZAM RIFQI
D3 PERPUSTAKAAN
100213300532
02
Soal !
Diketahui :
Ip address = 172.168.11.5
Netmask = 255.255.255.240
Ditanyakan :
A. Network id ?
B. Broadcast id ?
C. Range ip address yg bisa dipakai ?
Jawab !
A. Network id
Ip address = 172.168.11.5
Di ubah ke biner = 10101100.10101000.00001011.00000101
Netmask = 255.255.255.240
Di ubah ke biner =11111111.11111111.11111111.11110000
Ket : 1 AND 0 = 0 ( sebaliknya)
Network id = Ip address AND Netmask
10101100.10101000.00001011.00000101 AND
11111111.11111111.11111111.11110000
= 11111111.11111111.11111111.11110000
Jadi Network id = 172.168.11.0
B. Broadcast id
Ip address = 172.168.11.5
Di ubah ke biner = 10101100.10101000.00001011.00000101
Netmask = 255.255.255.240
Di ubah ke biner =11111111.11111111.11111111.11110000
~ Netmask = 00000000.00000000.00000000.00001111
Ket : 0 OR 1 = 1 (sebaliknya)
Broadcast id = Ip address OR ~ Netmask
10101100.10101000.00001011.00000101
00000000.00000000.00000000.00001111
= 10101100.10101000.00001011.00001111
Jadi broadcast id = 172.168.11.15
C. Range ip address yg bisa dipakai adalah 172.168.11.1 – 172.168.11.14
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